Using Newton's law of universal gravitation, show that T^2 is proportional to r^3 (where T is the orbital period of a planet around a star, and r is the distance between them).

(Lets consider a simple planetary system composed of a planet orbiting a star. the gravitational force between the two is given by F=(GMm)/(r2). Assuming the planet also moves in a circular orbit, we can consider the centripetal force, F=mω2r. As both gravitational and centripetal forces act in the same direction, we can equate them to find (GMm)/(r2)=mω2r.
We note that 'm' cancels and we can divide through by 'r' to arrive at GM/r32. ω is simply angular frequency given by ω =2π/T. Substituting this into our expression we find that GM/r3= 4π2/T2.After some simple rearranging, we note that  T=(4π2r3)/(GM). So  T2 is indeed proportional to  r3 . This simple statement is known as Kepler's third law of planetary motion.

Answered by Karanvir S. Physics tutor

18426 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Why is Kinetic Energy mv^2/2?


In a particle accelerator, you accelerate an electron. Afterwards, you measure it's energy to be 350 keV. Tell my why you can't find the speed from this energy using your knowledge of classical mechanics.


A spacecraft needs to be slowed down from a speed of 96m/s to 8.2m/s. This can be done by firing an object as the spacecraft is moving. If the mass of the spacecraft is 6730kg and the object is 50kg, calculate the velocity of the ejected object.


A projectile is launched from ground level with a speed of 25 m/s at an angle of 42° to the horizontal. What is the horizontal distance from the starting point of the projectile when it hits the ground?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy