2 Capacitors (c1 = 500mf) and (c2=300mf), are connected in parallel to a 10v d.c supply. Calculate the total capacitance of the circuit, and hence the total energy stored in the capacitors.

Use the equation Ct = C1 + C2, 500mF + 300mF = 800mF or 800x10^-3F 2) Appropriate equation is W=1/2 V^2 C W = (0.5)*(10^2)*800^-3 = 40J