Calculate the pH of the following solutions: 0.002 mol/dm^-3 KOH

pH by definition is given as -log10(cH+) or log10(1/cH+), where cH+ is the concentration of the H+ ions in the solution.Similarly, pOH= -log10(cOH-) pH + pOH= 14KOH is basic so we can calculate the pOH, which is pOH= -log10(cOH-)=-log10(0.002)= 2.69pH=14-2.69=11.31

CB
Answered by Csaba B. Chemistry tutor

9856 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

How to we increase the rate of a reaction?


Give the IUPAC name of CH3CH2CH2CH2CH(OH)CN


Explain, with reference to the electronic transitions involved, how characteristic flame colours of metal ions are formed and why the flame colours are different.


What is the difference between stereoisomerism and optical isomerism?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning