A charged particle in a cyclotron moves in a circle with radius 5mm. If the field in the cyclotron is 0.06 T and the velocity of the particle is 2.4x10^7, what is the charge-mass ratio of the particle?

Firstly, we should equate the centripetal force to the force on a moving charge using equations from our formula booklet: (force on a moving charge): F = Bqv(centripetal force): F = mv2/rmv2/r = Bqvwhen we cancel the 'v's' we get:mv/r = Bqmultiply both sides by r to get: Bqr = mvdivide through by m and divide through by 'Br' to get: q/m = v/BrThis now gives us an equation for the charge mass ratio (q/m) as: v/BrNow, substitute in your given values for v (velocity), B (magnetic field strength) and r (radius), ensuring you use the correct index form. 2.4x10^7 / (0.06 x 5x10^-3) = 8x10^10 = q/m

PV
Answered by Preshayla V. Physics tutor

2272 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Two students are provided with a starting pistol, a stopwatch and a long measuring tape. The starting pistol produces a loud sound and a puff of smoke. Describe how the students use the apparatus to calculate the speed of sound.


What is the momentum of a 84 kg man running at 5 m/s?


Explain the difference between energy and power.


What is the difference between nuclear fission and fusion?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning