How does electrophilic aromatic substitution occur?

The delocalised ring in aromatic compounds (such as benzene) is very stable and therefore requires a very strong electrophile to be created before it will react. An example of this would be the formation of the nitronium ion (NO2+) from sulfuric acid and nitric acid, where the nitric acid acts as a base by accepting a proton in the following reaction:H2SO4 + HNO3 -> HSO4- + NO2+ + H2OUsing the whiteboard I can then outline the mechanism for this reaction, showing how the nitronium ion breaks the aromatic delocalised ring, then the ring reforms by eliminating a hydrogen atom. This hydrogen atom then goes on to react with the hydrogen sulfate HSO4- ion to reform sulfuric acid, thus making sulfuric acid a catalyst in this reaction.We can draw parallels with this reaction to many other electrophilic substitution reactions such as chlorination, bromination and Friedel-Crafts alkylation reactions as they are all very similar in principle.

MP
Answered by Miles P. Chemistry tutor

2579 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

A buffer was made by mixing 20cm3 of 0.05M NaOH and 20cm3 of 0.25M propanoic acid. Calculate the pH. Ka=1.34x10^-5


What is an empirical formula and how do I calculate it?


Draw an Alkane with the molecular formula C4H8 as well as a possible functional group isomer and state a chemical test you can use to differentiate between the two.


Molecules of hydrogen chloride, HCl, and molecules of fluorine, F2, contain the same number of electrons. Hydrogen chloride boils at –85 °C and fluorine boils at –188 °C.Explain why there is a difference in the boiling points of HCl and F2.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning