Find the coordinates of the stationary points on the curve y=x^5 -15x^3

dy/dx = 5x4-45xby multiplying each term by the power and then decreasing the power by oneAt stationary points, dy/dx=0 since the function is neither increasing nor decreasing at a stationary point5x4-45x2=05x2(x2-9)=05x2(x-3)(x+3)=0 (Difference of two squares)Stationary points at x=0, x=3 and x=-3Plug each value into the original equation to get y coordinatesGet (0,0), (3, -162), (-3, 162)

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Answered by Shavon D. Further Mathematics tutor

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