What is the oxidation number of Mn in K2MnO4?

The oxidation number of an ion is the same as its charge. We know that the oxidation number of K+ is +1 and the oxidation number of O2- is -2, but we don't know the oxidation number of Mn so let's call that x. There are 2 K+ ions which makes +2 and 4 O2- ions which makes -8 (4*-2) and in K2MnO2 we know the charge of the molecule is neutral so the overall oxidation number must be 0. Therefore +2 (K) + x (Mn) + -8 (O) = 0 which means x = +6 so the oxidation number of Mn is +6 in K2MnO4.

AC
Answered by Alex C. Chemistry tutor

53353 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

What is optical isomerism and how can you distinguish between optical isomers?


Why is a nucleophilic substitution reaction between ammonia and benzene unlikely?


Why are complex ions containing transition elements coloured?


How do you form phenylamine from benzene? Include reagents and conditions and the name of the reactions


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning