Describe the forces acting on a skydiver jumping out of a plane and explain why opening a parachute reduces the velocity

Initially the air resistance (r) is low, and the force due to gravity (mg) is high. These forces are unbalanced so the skydiver accelerates downwards. (mg > r)As the velocity increases the force of air resistance increases (r becomes larger but mg stays the same)At the point where the downwards force of gravity and the upwards force of air resistance are the same (equal and opposite), the skydiver has reached terminal velocity and no longer accelerates (mg = r)Once the parachute is opened the air resistance is suddenly very large so there is a rapid deceleration since the forces are unbalanced once again. (r > mg)This deceleration continues until a new, slower terminal velocity has been reached (r = mg)

FJ

Related Physics GCSE answers

All answers ▸

How do I work out the efficiency of a process from a Sankey diagram?


On a pirate ship, a 1.6m plank is held at one end to the ship. A 65kg pirate walks the plank with his 1.1kg parrot following 40cm behind him. What is the total clockwise moment acting on the plank when the pirate reaches the end of it?


How do I solve this problem?


Explain Ohms Law