Person A, weighing 35 kg, is sitting 10m away from a seesaw pivot. Person B, weighing 50 kg, it sitting at the other end, at a distance d. Calculate d, in order for the seesaw not to topple over. (g=10m/s^2)

Force@A: FA = mA x g = 35 x 10 = 350NAnticlockwise moment: MA = FA x dA= 350 x 10 = 3500NmForce @B: FB=mb x g = 50 x 10 = 500NClockwise moment: Mc= FB x dBFor the seesaw to be in equilibrium, MA=Mc (1)But Mc= FBx dB (2)(1), (2) => MA = FBx dB => dB= MA/FB = 3500/500 =7m

AA
Answered by Antonia A. Physics tutor

1983 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

How do you calculate the total resistance of two resistors, R1 and R2, when they are in series and when they are in parallel?


Write the equations of motion for constant acceleration and describe each term involved. Explain how to apply these equations of motion to calculate the horizontal and vertical components of a projectile moving under the force of gravity only.


What is terminal velocity? (falling bodies)


Which are the forms of heat you know. Explain them briefly including an example


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning