Person A, weighing 35 kg, is sitting 10m away from a seesaw pivot. Person B, weighing 50 kg, it sitting at the other end, at a distance d. Calculate d, in order for the seesaw not to topple over. (g=10m/s^2)
Force@A: FA = mA x g = 35 x 10 = 350NAnticlockwise moment: MA = FA x dA= 350 x 10 = 3500NmForce @B: FB=mb x g = 50 x 10 = 500NClockwise moment: Mc= FB x dBFor the seesaw to be in equilibrium, MA=Mc (1)But Mc= FBx dB (2)(1), (2) => MA = FBx dB => dB= MA/FB = 3500/500 =7m
AA
Related Physics GCSE answers
All answers ▸A 70Kg person jumps out of a plane and deploys a parachute, once the parachute is open the wind resistance acting on the person and the parachute is 900N. What is the direction and magnitude of the persons acceleration.
Explain the difference between speed and velocity.
How do I remember all the formulas I will need for questions.
Calculate the acceleration if a force of 500N is exerted on a mass of 20kg