Person A, weighing 35 kg, is sitting 10m away from a seesaw pivot. Person B, weighing 50 kg, it sitting at the other end, at a distance d. Calculate d, in order for the seesaw not to topple over. (g=10m/s^2)
Force@A: FA = mA x g = 35 x 10 = 350NAnticlockwise moment: MA = FA x dA= 350 x 10 = 3500NmForce @B: FB=mb x g = 50 x 10 = 500NClockwise moment: Mc= FB x dBFor the seesaw to be in equilibrium, MA=Mc (1)But Mc= FBx dB (2)(1), (2) => MA = FBx dB => dB= MA/FB = 3500/500 =7m
AA
Related Physics GCSE answers
All answers ▸What is the conservation of energy?
If v = 10, a = 2 and t = 4, what is u
A roller coaster car starts stationary at the top of a downwards slope. At the bottom of the slope, it has a speed of 30m/s. Use the conservation of energy to find the vertical height of the slope. (Use g=10 m/s^2)
What is a moment?