Person A, weighing 35 kg, is sitting 10m away from a seesaw pivot. Person B, weighing 50 kg, it sitting at the other end, at a distance d. Calculate d, in order for the seesaw not to topple over. (g=10m/s^2)
Force@A: FA = mA x g = 35 x 10 = 350NAnticlockwise moment: MA = FA x dA= 350 x 10 = 3500NmForce @B: FB=mb x g = 50 x 10 = 500NClockwise moment: Mc= FB x dBFor the seesaw to be in equilibrium, MA=Mc (1)But Mc= FBx dB (2)(1), (2) => MA = FBx dB => dB= MA/FB = 3500/500 =7m
AA
Related Physics GCSE answers
All answers ▸State Newton's 2nd Law, and use this explain the vertical motion of a parachutist in the descent from her plane to Earth.
Imagine a box sliding down a rough slope. What will the free body diagram for the box look like?
How can an object accelerate without changing speed?
What is the resistance (in Ohms) of two 20 Ohm resisters in parallel?