I throw a ball straight up with an initial velocity of 2m/s. How high is it after a fifth of a second?

assign each variable to a value in s = ut + 1/2at2u = 2m/s t=0.2sa=-9.81m/s2so s = (2 x 0.2) + 1/2(-9.81)(0.2)2so s =

HA
Answered by Henry A. Physics tutor

2383 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

What is nuclear fusion?


Compare the advantages and disadvantages of the two methods of generating electricity (figure 1 in answer):


Explain why evaporation cools a liquid.


Alice drops an apple from a height of 2 m above the ground. Assuming there is no air resistance, what is the speed of the apple when it hits the ground?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning