what force does a person have to exert on one side of a seesaw if the other person weighs 70kg and is the same distance away from the pivot (2m) on the other side of the seesaw?

70kg x 9.8 = 686N x 2 = 1372 Nm, as 2m away again, divide by 2 = 868 Newtons

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Answered by Marcus B. Physics tutor

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