Find all of the roots of unity, Zn, in the case that (Zn)^6=1

Here we use the complex exponential form of 1 which is e^(i 2n pi). Applying the sixth root and substituting in for integer values of n gives all roots in complex exponential form.These can be converted into a complex number of the form a +ib by using e^ix = cosx +isinx

CR
Answered by Callum R. Further Mathematics tutor

2301 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Prove by induction that 2^(6n)+3^(2n-2) is divsible by 5. (AS Further pure)


Find the solution the the differential equation d^2y/dx^2 + (3/2)dy/dx + y = 22e^(-4x)


Given that x = i is a solution of 2x^3 + 3x^2 = -2x + -3, find all the possible solutions


Use De Moivre's Theorem to show that if z = cos(q)+isin(q), then (z^n)+(z^-n) = 2cos(nq) and (z^n)-(z^-n)=2isin(nq).


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences