Find all of the roots of unity, Zn, in the case that (Zn)^6=1

Here we use the complex exponential form of 1 which is e^(i 2n pi). Applying the sixth root and substituting in for integer values of n gives all roots in complex exponential form.These can be converted into a complex number of the form a +ib by using e^ix = cosx +isinx

CR
Answered by Callum R. Further Mathematics tutor

2465 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Calculate: ( 2+i√(5) )( √(5)-i).


What is a complex number?


Why does matrix multiplication seem so unintuitive and weird?!


What is the polar form of the equation: x^2+y^2 =xy+1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences