At what temperature does the reaction become feasible? When ΔH = 492.7 kJmol^-1 and ΔS = 542.6 JK^-1mol^-1.

When a reaction is feasible ΔG = 0. Rearrange the equation ΔG = ΔH - TΔS. So that when ΔG = 0,       T = ΔH / ΔS.

Must convert ΔS from JK^-1mol^-1 to kJK^-1mol^-1 by dividing it by 1000.

Then plug in numbers given so T = (492.7 kJmol^-1) / (0.5426 kJK^-1mol^-1) 

T = 908 K.

LW
Answered by Lily W. Chemistry tutor

20110 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Why does ionisation energy of elements generally decrease as you move down a group in the periodic table?


Define the "standard enthalpy change of atomisation".


How do you form phenylamine from benzene? Include reagents and conditions and the name of the reactions


Describe how to perform a flame test to identify an unknown compound.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning