At what temperature does the reaction become feasible? When ΔH = 492.7 kJmol^-1 and ΔS = 542.6 JK^-1mol^-1.
When a reaction is feasible ΔG = 0. Rearrange the equation ΔG = ΔH - TΔS. So that when ΔG = 0, T = ΔH / ΔS.
Must convert ΔS from JK^-1mol^-1 to kJK^-1mol^-1 by dividing it by 1000.
Then plug in numbers given so T = (492.7 kJmol^-1) / (0.5426 kJK^-1mol^-1)
T = 908 K.
LW
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