An electron moving at 1000 m/s annihilates with a stationary positron. What is the frequency of the single photon produced?

The first thing to be aware of is that the frequency of a photon will depend on two things, its wavelength (c=fλ ) and its energy (E=hf). There is no information regarding the wavelength of the photon, but we can work out its energy using conservation of energy arguments, i.e. the total energy of the electron and positron will be equal to the energy of the photon because after the annihilation both the positron and electron will have disappeared.The total energy of the electron and positron will be the sum of their kinetic energies (KE=1/2mv²) and the energy associated with their masses (E=mc²). Only the electron is moving hence only the electron has kinetic energy which can be calculated by KE_e = 1/2m_e1000² = 4.55510^-25 J where m_e = 9.1110^-31kg. The energy associated with the mass of the electron is E_e = m_ec² = 8.19910^-14 J. Because the positron is the antiparticle of the electron it has opposite charge but the same mass, hence its rest mass is also just E_e. Therefore, the total energy before the annihilation is 2E_e+ KE_e = 1.639810^-13 J. Using E_photon= hf, we can divide our calculated value by the Planck constant (h = 6.6310^-34 Js) to obtain the frequency, f, getting out f = 2.4710²⁰ Hz.