calaculate the resistance if two 3 ohm resitsors are placed in series and another 3 ohm was attached in parallel
total resistance for resistors in series is the addition of the resistances therefore the two 3 ohm resisters in series totals 6 ohms resistors in parallel follow the equation : 1/RT = 1/R1 + 1/R2therefore total resistance = (1/6 + 1/3)-1RT = 2 ohms
BA
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