An electron is accelerated through a uniform electric field of strength, E= 20 [N/C]. Determine the speed after the the electron travels 0.5 m from rest.

E=F/Q. F= 20*(1.6910^-19)=3.3810^-18NF=ma m=9.1110-31 kgTherefore, a = 3.71 * 10^12 m/s^2Since v^2= u^2 + 2as and s= 0.5m,Then v=1.9310^6 m/s

LF
Answered by Luke F. Physics tutor

2276 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

What determines the acoustic impedance of a material and why is it useful in understanding ultrasound imaging?


How would you calculate the vertical and horizontal components of the velocity of an object with an initial velocity of 15m/s which is travelling upwards at an angle of 30 degrees to the horizontal?


An ideal gas at a temperature of 22 C is trapped in a metal cylinder of volume 0.2 m^3 at a pressure of 1.6x10^6 Pa. The gas has a molar mass of 4.3 x 10^(-2) kg mol^(-1). Calculate the density of the gas in the cylinder.


What is the Quark structure, Baryon number, and antiparticle of a kaon, K+, which has a strangeness of 1.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning