An electron is accelerated through a uniform electric field of strength, E= 20 [N/C]. Determine the speed after the the electron travels 0.5 m from rest.
E=F/Q. F= 20*(1.6910^-19)=3.3810^-18NF=ma m=9.1110-31 kgTherefore, a = 3.71 * 10^12 m/s^2Since v^2= u^2 + 2as and s= 0.5m,Then v=1.9310^6 m/s
LF
Related Physics A Level answers
All answers ▸Why does an α particle cause more ionisation than a β particle if they have the same kinetic energy?
What distance is one Parsec
describe how a microwave oven works (EM waves + thermal physics)
A ball is rolled, travelling 10 m north in 5s, then 10 m east in 10s. What is the total distance and average speed of the ball? What is the total displacement and average velocity of the ball?