An electron is accelerated through a uniform electric field of strength, E= 20 [N/C]. Determine the speed after the the electron travels 0.5 m from rest.
E=F/Q. F= 20*(1.6910^-19)=3.3810^-18NF=ma m=9.1110-31 kgTherefore, a = 3.71 * 10^12 m/s^2Since v^2= u^2 + 2as and s= 0.5m,Then v=1.9310^6 m/s
LF
Related Physics A Level answers
All answers ▸State Lenz's law and hence describe and explain what happens to a magnet travelling through a metal tube
Two identical uniform spheres each of radius R are placed in contact. The gravitational force between them is F. They are then separated until the force between them is one ninth of the magnitude. What is the distance between the surfaces of the spheres?
You are asked to find the Young modulus for a metal using a sample of wire. *(a) Describe the apparatus you would use, the measurements you would take and explain how you would use them to determine the Young modulus for the metal.
Do heavier objects fall on the ground quicker?