Solve (sec (x))^2 + 2tan(x) = 0
Using the trigonometric identity: (sec(x))^2 = (tan(x))^2 + 1 we get to (tan(x))^2 + 2tan(x) + 1 = 0. We can express this result as the multiplication of 2 equal factors arriving at (tan(x) + 1)^2 = 0. This leads us to tan(x) = -1. Therefore the answers will be x=3pi/4, 7pi/4
LL
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