Solve (sec (x))^2 + 2tan(x) = 0
Using the trigonometric identity: (sec(x))^2 = (tan(x))^2 + 1 we get to (tan(x))^2 + 2tan(x) + 1 = 0. We can express this result as the multiplication of 2 equal factors arriving at (tan(x) + 1)^2 = 0. This leads us to tan(x) = -1. Therefore the answers will be x=3pi/4, 7pi/4
LL
Related Maths IB answers
All answers ▸Talk about the relation between differentiability and continuity on a real function and its derivative.
How do I show (2n)! >= 2^n((n!)^2) for every n>=0 by induction?
How do I derive the indefinite integral of sine?
In Topic 5 (Statistics and Probability) what is the difference between mutually exclusive events and independent events?