Answers>Maths>IB>Article

Solve (sec (x))^2 + 2tan(x) = 0

Using the trigonometric identity: (sec(x))^2 = (tan(x))^2 + 1 we get to (tan(x))^2 + 2tan(x) + 1 = 0. We can express this result as the multiplication of 2 equal factors arriving at (tan(x) + 1)^2 = 0. This leads us to tan(x) = -1. Therefore the answers will be x=3pi/4, 7pi/4

LL
Answered by Lina L. Maths tutor

1951 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

Prove that (sinx)^2 + (cosx)^2 = 1


Consider the functions f and g where f(x)=3x-5 and g(x)=x-2. (a) Find the inverse function for f. (b) Given that the inverse of g is x+2, find (g-1 o f)(x).


How does the right angle triangle definition of sine, cosine and tangent relate to their graphs as a function of angle and to Euler's formula?


When integrating by parts, how do I decide which part of the integrand is u or f(x) and which dv or g'(x)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning