If a car drives at 5 ms^-1 for 10 seconds and then 6 ms^-1 for 5 seconds, how far has it travelled in total?
The equation used here is speed = distance / time (s=d/t). Firstly the 30 ms^-1. Rearrange the equation to find distance (st=d). 5ms^-1 x 10s = 50m. The second stint is 6ms^-1 x 5s = 30m. This makes the total distance as 30m + 50m = 80m.
MP
Related Physics GCSE answers
All answers ▸A particle of mass 5kg is acted upon by a force of 400N for a distance of 20m along the x axis. What is its final velocity if it is initally at rest?
Simon's car has run out of fuel. He must push his car 5 metres to the petrol pump, using a force of 200N. How much work does Simon do?
A ball of mass 1kg is rolled down a hill of height 10m. At the bottom it collides with another ball of mass 5kg. What speed does the second ball move away with? You can assume the collision between the balls is elastic.
Two identical objects have a charge of magnitude q. If r is the distance bethween them, what should their mass be so that the objects are balanced.