If a car drives at 5 ms^-1 for 10 seconds and then 6 ms^-1 for 5 seconds, how far has it travelled in total?
The equation used here is speed = distance / time (s=d/t). Firstly the 30 ms^-1. Rearrange the equation to find distance (st=d). 5ms^-1 x 10s = 50m. The second stint is 6ms^-1 x 5s = 30m. This makes the total distance as 30m + 50m = 80m.
MP
Related Physics GCSE answers
All answers ▸What is the law of conservation of energy?
Using the principle of the conservation of energy, calculate the maximum speed of a ball of 5.0kg that has been dropped from a height of 20m. (Given that the gravitational field strength is equal to 9.8N/kg)
The charge that flows through the shower in 300 seconds is 18000C. The electric shower has a power of 13.8 kW. Calculate the resistance of the heating element in the shower.
What is the Doppler effect and how is it exploited in everyday life?