If a car drives at 5 ms^-1 for 10 seconds and then 6 ms^-1 for 5 seconds, how far has it travelled in total?

The equation used here is speed = distance / time (s=d/t). Firstly the 30 ms^-1. Rearrange the equation to find distance (st=d). 5ms^-1 x 10s = 50m. The second stint is 6ms^-1 x 5s = 30m. This makes the total distance as 30m + 50m = 80m.

MP
Answered by Marcus P. Physics tutor

2579 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Energy generation can occur in both renewable and non-renewable ways. Part a) List three methods of non-renewable energy generation. Part b) List 2 methods of renewable energy generation. [Bonus] Part c) Why might it be beneficial to use renewable?


How does a hydraulic jack work and how do I work out the pressures involved?


Assuming no friction, describe the motion of a simple pendulum released from rest at t=0 at amplitude A? Provide information about its speed and position at characteristic times during one period. [The 1D equation of motion is described by a cosine]


What is the difference between a transverse and longitudinal wave?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning