If a car drives at 5 ms^-1 for 10 seconds and then 6 ms^-1 for 5 seconds, how far has it travelled in total?

The equation used here is speed = distance / time (s=d/t). Firstly the 30 ms^-1. Rearrange the equation to find distance (st=d). 5ms^-1 x 10s = 50m. The second stint is 6ms^-1 x 5s = 30m. This makes the total distance as 30m + 50m = 80m.

MP
Answered by Marcus P. Physics tutor

2781 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

What is red shift?


What do geostationary satellites do?


Ann and Bob play on a uniform seesaw. The seesaw is 4m long and Ann and Bob weigh 600N and 800N respectively. If both Ann and Bob start at one end of the seesaw and Bob starts to walk up the seesaw at 2m/s, after how long will the seesaw turn?


A car accelerates (at a constant acceleration) from a velocity of 25m/s to 34m/s in 6s. Calculate the cars acceleration.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning