express z(2+i)=(1+2i)^2 in the form z=x+iy

rearrange gives z = [(1+2i)^2]/(2+i)expanding (1+2i)^2 gives 4i-3 therefore this becomes (4i-3)/2+i multiply that by the conjugate (2-i)/(2-i) to give (11i-2)/5therefore z= -2/5 + 11i/5

HH
Answered by Huy H. Further Mathematics tutor

2613 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Solve x^(-1/4) = 0.2


To differentiate a simple equation: y= 4x^3 + 7x


The coefficient of the x^3 term in the expansion of (3x + a)^4 is 216. Find the value of a.


Use the factor theorem to show that (x-1) is a factor of x^3 - 3x^2 -13x + 15


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning