A 1kg ball is dropped of a 20m tall bridge onto tarmac. The ball experiences 2N of drag throughout its motion. The ground has a coefficient of restitution of 0.5. What is the maximum height the ball will reach after one bounce

Energy
GPE of the ball on the bridge: MGH = 1 * 9.81 * 20 =196 J
energy lost to drag = F * D = 2 * 20 = 40 J
Velocity of the ball just before impact =sqr(2*(196-40)/1) =17.66 m/s
Velocity of the ball just after impact = 17.660.5 = 8.83 m/s
Kinetic energy just after impact 0.5 * 1 * 8.83^2 =39 J
Equation for final height (using energy)
KE = Drag energy + GPE
39 = 2
H + 19.81H
H=3.30m

MD
Answered by Max D. Further Mathematics tutor

1987 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Find the general solution for the determinant of a 3x3 martix. When does the inverse of this matrix not exist?


The ODE mx'' + cx' + kx = 0 is used to model a damped mass-spring system, where m is the mass, c is the damping constant and k is the spring constant. Describe and explain the behaviour of the system for the cases: (a) c^2>4mk; (b) c^2=4mk; (c) c^2<4mk.


how do I do proofs by induction?


Solve the differential equations dx/dt=2x+y+1 and dy/dt=4x-y+1 given that when t=0 x=20 and y=60. (A2 Further pure)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences