How many (1/6)'s are there in 4 & 1/2?

  1. The first step is to work out how many (1/6) there are in one whole. 6 x (1/6) = 1.
    2)The next step uses partitioning. Split the 4 & (1/2) into a separate (4) and then (1/2)
    3) Work out how many (1/6)'s there are in 4, after working out how many (1/6)'s are in 1. 4 is divisible by (1) (4) times. Therefore, to work out how many (1/6)'s are in (4) would require that you multiply the number of (1/6)'s by the number of whole numbers (4). 6 x 4 = 24 (1/6)'s.
    4) Now that it has been established that there are 24 (1/6)'s in the whole number 4, it is time to work out how many (1/6)'s are in (1/2). First, we change the fractions so that there is a common denominator. By establishing that the common denominator of the (1/6) is divisible by the common denominator of the other fraction (1/2), we calculate that the denominator of the latter (last fraction) is multiplied by 3 to achieve a common fraction.
    5)What is applied to the 'top' number is also applied to the bottom when converting fractions. If the denominator has been multiplied by 3, then the numerator must also be multiplied by 3. Therefore, the fraction (1/2) is now equal to (3/6).
    6)Work out how many (1/6)'s are in (1/2) or (3/6). This is equal to 3.
    6). Work out the total number of (1/6)'s in (4 & 1/2) by adding the number of individual (1/6)'s calculated during the partitioning. 24 (1/6) + 3 (1/6) = a total of 27 (1/6)'s in the number 4 & 1/2.
RM
Answered by Rimah M. Maths tutor

10235 Views

See similar Maths 11 Plus tutors

Related Maths 11 Plus answers

All answers ▸

3/4 +5/3 = ?


The point p lies on the curve with eqn x = (4y - sin(2y)^2, given that p has coordinates (p,π/2), p is a constant, a) find the exact value of p; the tangent to the curve at P cuts the y-axis at A, b) use calculus to find the coordinates of A.


If one side of rectangle is 2 times longer than other one and the area of that rectangle is 32, what is the length of shorter side?


What is the sum of the factors of 21?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning