Part a) Draw the mechanism of the attack of CN- on CH3COCH3 in the presence of HCN Part b) Explain why the product of this reaction does not rotate the plane of plane polarised light

Part a) 1 mark : Show the nucleophilic attack of CN- at the carbonyl forming the O-1 mark : Show the protonation of the O- via the deprotonation of HCNPart b)1 mark: Student has identified that the intermediate has a trigonal planar structure1 mark: Student has detailed that the nucleophile (CN-) can attack from either side1 mark: A racemic mixture or 50:50 split of enantiomers that rotate light in opposite directions has been formed leading to no overall effect on the plane of plane polarised light.

NH
Answered by Noah H. Chemistry tutor

3396 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Propane and Chlorine react in the presence of UV light to give 2-chloropropane and HCl. Estimate the enthalpy change of this reaction using the following bond enthaplies (KJ/mol) : C-H=+413, Cl-Cl=+243, C-Cl=+346 and H-Cl=+432.


Why does phenol react more readily with bromine than benzene?


What is meant by terms 'saturated' and 'unsaturated' when applied to alkanes and alkenes? Describe a chemical test to distinguish between the liquids hexane and hexene.


How do mass spectrometers measure the mass of a compound?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning