Part a) Draw the mechanism of the attack of CN- on CH3COCH3 in the presence of HCN Part b) Explain why the product of this reaction does not rotate the plane of plane polarised light

Part a) 1 mark : Show the nucleophilic attack of CN- at the carbonyl forming the O-1 mark : Show the protonation of the O- via the deprotonation of HCNPart b)1 mark: Student has identified that the intermediate has a trigonal planar structure1 mark: Student has detailed that the nucleophile (CN-) can attack from either side1 mark: A racemic mixture or 50:50 split of enantiomers that rotate light in opposite directions has been formed leading to no overall effect on the plane of plane polarised light.

NH
Answered by Noah H. Chemistry tutor

3615 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

The equilibrium N2O4 (g) -->--< 2NO2 (g) is set up when N2O4 dissociates. When 0.0370 moles of N2O4 dissociates at 25 degrees in a 0.5dm3 sealed container, 0.0310 moles of N2O4 remains at equilibrium. Calculate the value of Kc for this reaction.


What is the difference between ionic and metallic bonding?


Why does water have a higher boiling point than methane?


What is the order of decreasing acidity for the molecules phenol, ethanoic acid and ethanol? Why?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning