Answers>Maths>Scottish Highers>Article

Solve log_2(3x + 7) = 3 + log_2(x – 1), x > 1.

Begin by collecting log_2 terms.log_2(3x + 7) - log_2(x – 1) + = 3 Using the rule of log terms we getlog_2((3x+7)/(x-1)) = 3 (3x+7)/(x-1) = 2³3x+7 = 8(x-1)3x+7-8x+8 = 0 -5x+15 = 0 x= 3

Answered by Catriona F. • Maths tutor

1924 Views

See similar Maths Scottish Highers tutors

Solve log_2(3x + 7) = 3 + log_2(x – 1), x > 1.

Related Maths Scottish Highers answers

Find ∫((x^2−2)(x^2+2)/x^2) dx, x≠0

Solve algebraically the following system of equations: 4x + 5y = -3; 6x - 2y = 5

Work out the angle between the two tangents of the curve y = sin(x) at y = 0 and y = 1

Given f(x) = (x^(2)+(3x)+1)/(x^(2)+(5x)+8), find f'(x) and simplify your answer.

We're here to help

Company Information

Popular Requests

© MyTutorWeb Ltd 2013–2025

CLICK CEOP

Solve log_2(3x + 7) = 3 + log_2(x – 1), x > 1.

Related Maths Scottish Highers answers

Find ∫((x^2−2)(x^2+2)/x^2) dx, x≠0

Solve algebraically the following system of equations: 4x + 5y = -3; 6x - 2y = 5

Work out the angle between the two tangents of the curve y = sin(x) at y = 0 and y = 1

Given f(x) = (x^(2)+(3*x)+1)/(x^(2)+(5*x)+8), find f'(x) and simplify your answer.

We're here to help

Company Information

Popular Requests

© MyTutorWeb Ltd 2013–2025

CLICK CEOP

Given f(x) = (x^(2)+(3x)+1)/(x^(2)+(5x)+8), find f'(x) and simplify your answer.