NaOH is a strong base. An aqueous solution is made containing 0.300mol.dm^-3 of NaOH at room temperature. Calculate the pH of this solution.

Concentration of NaOH=Concentration of OH- ions (NaOH is a strong base)

Kw=1x10^-14 (at room temperature/25 degrees)

using Kw=[H+][OH-]

We can figure out the [H+]

[H+]=Kw/[OH-]

[H+]=(1x10^-14) / (0.300)

Now we can put our concentration of H+ value into -log[H+] to find the pH using the fact pH=-log[H+]

pH=13.48

NK
Answered by Nadine K. Chemistry tutor

16667 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

A buffer solution was formed by mixing 20.0 cm^3 of sodium hydroxide solution of concentration 0.100 mol dm^–3 with 25.0 cm^3 of ethanoic acid of concentration 0.150 mol dm^–3. CH3COOH + NaOH---CH3COONa + H2O Calculate the pH of this buffer solution.


Describe and explain the trend in reactivity of Group 2 elements with chlorine as the group is descended?


What is a chiral carbon?


Explain, in terms of frequencies, why solutions of transition metal ions are often coloured.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning