NaOH is a strong base. An aqueous solution is made containing 0.300mol.dm^-3 of NaOH at room temperature. Calculate the pH of this solution.

Concentration of NaOH=Concentration of OH- ions (NaOH is a strong base)

Kw=1x10^-14 (at room temperature/25 degrees)

using Kw=[H+][OH-]

We can figure out the [H+]

[H+]=Kw/[OH-]

[H+]=(1x10^-14) / (0.300)

Now we can put our concentration of H+ value into -log[H+] to find the pH using the fact pH=-log[H+]

pH=13.48