Calculate the rate of change of d(t )=2/(3t), t ≠ 0, when t=6.

When a question asks for rate of change, this means you need to differentiate the equation. First you need to put the equation into differentiable a form ie, with the no variables on the denominator: f(t) = 2/3t^-1Then you can differentiate by multiplying the coefficient by the power and then reducing the power by one: f'(t)= -2/3t^-2We can put this back to a standard form to make it easier to work with: f'(t) = -2/(3t^2)Substitute t = 6 in and we get: f-(t) = -2/(3*36) = -2/108 = -1/54

LI
Answered by Lucy I. Maths tutor

2330 Views

See similar Maths Scottish Highers tutors

Related Maths Scottish Highers answers

All answers ▸

a) Factorise: 2x^2-72, and hence b) find the y-intercept of the line with the equation: y=(2x^2-72)/(4x-24)


A circle has equation x^2+y^2-8x+10y+41=0. A point on the circle has coordinates (8,-3). Find the equation of the tangent to the circle passing through this point.


A circle has equation x^2+y^2+6x+10y-7=0. Find the equation of the tangent line through the point on the circle (-8,-1).


Solve log_2(3x + 7) = 3 + log_2(x – 1), x > 1.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning