When the current through an ohmic conductor is 2A, the potential difference across it is 6V. What is the potential difference across the same ohmic conductor when the current is increased to 3A?

To answer this, you need to pick up on the clues in the question. "Ohmic conductor" is explicitly mentioned twice, so this is likely to be important. You should know that for ohmic conductors, p.d. is proportional to current, which means p.d./current=constant (called the constant of proportionality). You can calculate the constant from the first part of the question, 6/2=3.Now you know the constant, rearrange the equation to make what you want to find out, the p.d., the subject:p.d.=constantcurrentNow, you can use this equation and put in the numbers you know: p.d.=33=9V (don't forget the units!)If you'd prefer, you can also solve this using a graph. Draw a straight-line graph that cuts through zero-zero, with p.d. on the y-axis and current on the x-axis. The constant of proportionality is the gradient of the line, and can be found by finding difference in two y values (6-0) and dividing by difference in two x values (2-0). You can then use the equation above to find the p.d. in the second scenario, and you should get the same answer, 9V.

Answered by Eleanor Grace G. Physics tutor

2260 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Explain the difference between a battery and a cell


Describe the basic principles of ultrasound imaging (2 marks)


A musical instrument produces a sound wave with a frequency of 1000 Hz. The sound wave has a wavelength of 0.34 m in air. Calculate the speed of the sound wave in air.


a )John heats up 2kg of water from 20 degrees c to 80 degrees c. How much energy input did this require? b )When John weighs the water at the end, he has less than he started with. Why might this be? c) What hazards are in this experiment?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy