Differentiate: y=x^x

First take log’s each side as it would turn our complicated function into something differentiable by chain rule.
ln y = x*ln x
Then differentiate y with respect to x:
d(ln y)/dx = ln x + 1
1/y * dy/dx = ln x +1
dy/dx = y(ln x +1)
As we know what y is the final result is dy/dx= x^x(ln x +1)

MV
Answered by Mihai V. Further Mathematics tutor

2313 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Can you show me how to solve first order differential equations using the integrating factor method?


Prove by mathematical induction that 11^n-6 is divisible by 5 for all natural numbers n


Sketch the locus of z on an Argand diagram if arg[(z-5)/(z-3)] = π/6


What is a complex number?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning