The recommended daily allowance of methionine for an adult is 15 mg per kg of body mass. Tuna contains 755 mg of methionine per 100 g portion. Calculate the mass, in grams, of tuna that would provide the RDA of methionine for a 60 kg adult.

15mg per kilo recommended dose 15x60 = 900mg recommended dose for a 60kg adult There is 755mg per 100g portion of tuna So 900/755 = 1.19 times the amount in 100g of tuna is the recommended dose 1.19 x 100 = 119 119g of tuna is the amount that would provide the total recommended dose for a 60kg adult

DC
Answered by Darragh C. Chemistry tutor

5624 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

How does radiocarbon dating work?


Why is phenol more reactive than benzene?


Explain the geometry and bond angles in a NH3 molecule


What is an enthalpy change?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning