## MYTUTOR SUBJECT ANSWERS

1868 views

### 1.5 g of hydrocarbon undergoes complete combustion to give 4.4 g of CO2 and 2.7 g of H2O. Given this data, what is the empirical formula of this hydrocarbon?

The first step here is to determine the mass of C in CO2 and the mass of H in H2O. This is done by dividing the atomic mass by the molecular mass and then multiplying by the mass of compound produced.

For C:

(12.011 g / 44.009 g) x 4.40 g = 1.1999 g

For H:

(1.0079 x 2 / 18.0148 g) x 2.70 g = 0.3021 g

The next step is to convert these masses into moles. This is done by dividing the mass by the relative atomic mass of the element:

C: 1.1999 g / 12.011 g mol-1 = 0.0999 mol

H: 0.3021 g / 1.0079 g mol-1 = 0.2997 mol

The final step is to divide each of these two values by the smallest number, in this case this is the number of moles of carbon:

C: 0.0999 mol / 0.0999 mol = 1

H: 0.2997 mol / 0.0999 mol = 3

We therefore have a ratio of 1 carbon atom to 3 hydrogen atoms, thus the empirical formula for this hydrocarbon is CH3.

2 years ago

Answered by Joshua, an A Level Chemistry tutor with MyTutor

## Still stuck? Get one-to-one help from a personally interviewed subject specialist

#### 173 SUBJECT SPECIALISTS

£20 /hr

Degree: Medicinal and biological chemistry (Integrated Masters) - Nottingham University

Subjects offered:Chemistry, Maths+ 1 more

Chemistry
Maths
Biology

“Hi! I'm a Chemistry student studying at the University of Nottingham with a passion for science that I'd love to pass on to my tutees!”

MyTutor guarantee

£22 /hr

Degree: Chemical Engineering (Masters) - Bath University

Subjects offered:Chemistry, Science+ 3 more

Chemistry
Science
Physics
Maths
Further Mathematics

“Hey there! I am Laura and I am currently studying Chemical Engineering at University of Bath. I am really passionate about Science and I am willing to share my knowledge through tutoring you. My passion and expertise in science can be...”

£20 /hr

Degree: MBBS (Bachelors) - Kings, London University

Subjects offered:Chemistry, Maths+ 5 more

Chemistry
Maths
Human Biology
Classical Civilisation
.UKCAT.
-Personal Statements-

“”

#### About the author

Currently unavailable: for regular students

Degree: Chemistry (Masters) - Sheffield University

Subjects offered:Chemistry, -Personal Statements-

Chemistry
-Personal Statements-

“Hello everyone!I am currently in my fourth and final year of a masters degree in chemistry at the University of Sheffield.I am here to help you with any problems you may have in chemistry, at any levels. University friends often co...”

MyTutor guarantee

### You may also like...

#### Posts by Joshua

0.250 g of a hydrocarbon known to contain carbon, hydrogen and oxygen was subject to complete combustion and produced 0.3664 g of CO2 and 0.1500 g of H2O. What is the empirical formula of this hydrocarbon?

1.5 g of hydrocarbon undergoes complete combustion to give 4.4 g of CO2 and 2.7 g of H2O. Given this data, what is the empirical formula of this hydrocarbon?

24 g of Magnesium reacts with 16 g of Oxygen to produce 40 g of magnesium oxide. What mass of magnesium would you need to produce 10 g of magnesium oxide?

The relative formula mass of CaO is 56 and the relative formula mass of CO2 is 44. What is the mass of CaO that can be obtained from 200 g of CaCO3. CaO3 -> CaO + CO2

#### Other A Level Chemistry questions

0.250 g of a hydrocarbon known to contain carbon, hydrogen and oxygen was subject to complete combustion and produced 0.3664 g of CO2 and 0.1500 g of H2O. What is the empirical formula of this hydrocarbon?

The ratio between the molar mass of an alkene(A) and an alkyne(B) with the same number of carbon atoms is 1.05. Find the molecular formulas of the two hydrocarbons then write the reaction for how we can obtain the alkene A from the alkyne B.

What is entropy?

How do buffers work?

We use cookies to improve your site experience. By continuing to use this website, we'll assume that you're OK with this.