A baseball player strikes a ball with an initial velocity of 43ms^-1 at an angle of 32° to the horizontal. How far does the ball travel horizontally in 4 seconds?
Since the Initial velocity has a direction that is 32° to the horizontal we can split the velocity into it's components. The horizontal component of the velocity is vx = 43cos(32) (m/s). Since distance = velocity x time, In 4 seconds the ball will travel d = 43cos(32) x 4 (m). This is equal to d = 145.86m
JL
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