A baseball player strikes a ball with an initial velocity of 43ms^-1 at an angle of 32° to the horizontal. How far does the ball travel horizontally in 4 seconds?

Since the Initial velocity has a direction that is 32° to the horizontal we can split the velocity into it's components. The horizontal component of the velocity is vx = 43cos(32) (m/s). Since distance = velocity x time, In 4 seconds the ball will travel d = 43cos(32) x 4 (m). This is equal to d = 145.86m

JL
Answered by Jack L. Physics tutor

1871 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

A skydiver is at a height of 10,000 m. Assuming no air resistance, how fast is the skydiver travelling at 9,990 m above the ground?


Describe the energy transfers taking place when a person is running up a hill


Jane drops a football from the roof onto the ground below. The ball weighs 0.8kg and the distance the ball falls is 5m. Assuming there are no external forces acting on the ball, what speed will the ball be travelling at just before it hits the ground?


What led to the Plum Pudding model being replaced by Rutherford's nuclear model of the atom? (6 marks)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning