In the presence of ultraviolet radiation, cyclohexane reacts with bromine. A mixture of cyclic products are formed, including C6H11Br. Discuss each step of this reaction providing equations to show the mechanism.

INITIATION: Br2 --> 2Br . The breaking of the Br2 bond from ultraviolet radiation forms two radicals, as one electron from the bond pair goes to each bromine atom. This is called homolytic fission. PROPAGATION: C6H12 + Br . --> C6H11 . + HBr C6H11 . + Br2 --> C6H11Br + Br . There are multiple TERMINATION outcomes: C6H11 . + Br . --> C6H11Br C6H11 . + C6H11 . --> C12H22 Br . + Br . --> Br2

LK
Answered by Lisa K. Chemistry tutor

18225 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

What is a buffer and what do you need to make one?


State the H-O-H bond angle of a water molecule and explain why this is the case.


Describe how you would distinguish between separate samples of the two 2 0 4 stereoisomers of CH3CH2CH2CH2CH(OH)CN [2 marks]


How does Le Chatelier's Principle allow you to predict the change of the position of equilibrium for an equilibrium reaction?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning