In the presence of ultraviolet radiation, cyclohexane reacts with bromine. A mixture of cyclic products are formed, including C6H11Br. Discuss each step of this reaction providing equations to show the mechanism.

INITIATION: Br2 --> 2Br . The breaking of the Br2 bond from ultraviolet radiation forms two radicals, as one electron from the bond pair goes to each bromine atom. This is called homolytic fission. PROPAGATION: C6H12 + Br . --> C6H11 . + HBr C6H11 . + Br2 --> C6H11Br + Br . There are multiple TERMINATION outcomes: C6H11 . + Br . --> C6H11Br C6H11 . + C6H11 . --> C12H22 Br . + Br . --> Br2

LK
Answered by Lisa K. Chemistry tutor

19139 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

An alcohol, X has an Mr of 74 and percentage composition of 64.9% Carbon, 13.5% Hydrogen and 21.6% Oxygen. It does not turn potassium dichromate (VI) green. Determine the structural formula of X, and state its name.


Explain the trend in boiling points for the group 6 hydrides (O,S,Se,Te). Diagram would be included.


What is the difference between a Bronsted Lowry acid and a Lewis Acid?


Why is phenylamine a weaker organic base than ethylamine?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning