Given the following equilibrium: H2O + H2O <-> H3O+ + OH- and the Kw = 10^-14, determine the concentration of OH- species after the addition of 1 mmol of HCl to 1 L of neutral water.
As HCl is a strong acid, it will fully dissociate in water, releasing 1 mmol of H+, which will be the final concentration of protons in solution. The autoprotolysis equilibrium of water (or Kw) at 25 ºC is defined as [H+] x [OH-] = 10-14Therefore [OH-] = 10-14 / 1 = 10-14 mmol
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