Solve Simultaneous equations: 3x + 4y = 23 & 2x + 3y = 16
We need to cancel one of the variables (the x or y) out. Find the LCM of x or y.e.g. for x --> 6Multiply the WHOLE eqn to get 6x. So multiply the 1st eqn by 2 and the 2nd by 3[1] 6x + 8y = 46[2] 6x + 9y = 48 Then cancel out the x by subtracting one eqn from the other.e.g. [2] - [1] => y = 2Now sub y into one of the eqns that we started with2x + 3(2) = 162x + 6 = 162x = 10x = 5ANSWER: y = 2 & x = 5
EE
Related Maths KS3 answers
All answers ▸Solve the simultaneous equations: 2 + 5y = 3x, x + y = 6
Bob buys 33 pens and 21 rulers for £6. A ruler costs 8 pence more than a pen. How much does one pen cost?
How would you solve (4y + 3)/5 + (3y+1)/2 = 4 for y?
This rectangle is twice as long as it is wide. The perimeter of the rectangle is 30cm. What is the area?