How would you solve (4y + 3)/5 + (3y+1)/2 = 4 for y?

The first step is to remove the fractions in the equation, as the equation is easier to solve when there are only whole numbers.To remove the first fraction we should times the entire equation by 5 ----> 4y + 3 + 15y+5)/2 = 20 <-- It is important to remember to times both sides of the equation - students tend to forget this!To remove the second fraction we should times the entire equation by 2 ---> 8y + 6 + 15y + 5 = 40The next step is to move all the y's to one side and all the numbers to the other side ---> 23y = 40 - 6 - 5 ---> 23y=29Now that we know what 23y is equal to, to find out what y is equal to we must divide 29 by 23Therefore y = 29/23

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Answered by Nima S. Maths tutor

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