Find the gradient of the straight line with equation 4x+3y=12
To answer the question the equation given must be rearranged into the straight line formula, y=mx+c, where m is the gradient of the slopeminus 4x from both sides, we now have 3y=12-4xthen divide through by 3, so we now have y=4-4/3xand now rearrange into form y=mx+c, so we have y=-4/3x+12now the gradient can clearly been seen as -4/3
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