A particle is moving in a straight line from A to B with constant acceleration 4m/s^2. The velocity of the particle at A is 3m/s in the direction AB. The velocity of the particle at B is 18m/s in the same direction/ Find the distance from A to B.

First draw a diagram to see the set-up.Then look at SUVAT to see which values we have been given. In this case it is a=4, u=3,v=18 and s=?. The only letter not used from SUVAT is the t so we use the formula without... v2=u2+2as. Fill in the numbers 182=32+2 x 4 x s324 = 9+ 8s. Rearranges = (324-9)/8 = 39.375 m

AK
Answered by Adam K. Further Mathematics tutor

2718 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Find the coordinates of the minimum/maximum of the curve: Y = 8X - 2X^2 - 9, and determine whether it is a maximum or a minimum.


3x^3 -2x^2-147x+98=(ax-c)(bx+d)(bx-d). Find a, b, c, d if a, b, c, d are positive integers


express z(2+i)=(1+2i)^2 in the form z=x+iy


Factorise the following quadratic x^2 - 8 + 16


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences