Answers>Maths>IB>Article

Solve the equation sec^2(x) - 4tan(x)= -3 , 0 ≤x≤ 2π

To solve this problem, we have to look at some trig. identities that will help us simplify the problem.The formula booklet is always a great place to start! You can find that sec^2(x) = 1 + tan^2(x). Substituting this into the equation yields tan^2(x) + 1 - 4tan(x) = -3 Move the three over, and you will have tan^2(x) - 4tan(x) + 4 = 0 From here, you can factorize to [ tan(x) - 2 ] ^2 = 0, which gives you tan x = 2arctan(2) = 1.01 radians (63.4 degrees), 4.25 radians (243.4 degrees)
One common point that catches people out is they forget to put two solutions instead of one. Remember, that for any trigonometric function, it will repeat itself in a cyclical manner. Think of the graph, and even sketch it out to get a rough idea of where your solutions will fall, so that you can reach the answer more quickly and accurately

PH

Related Maths IB answers

All answers ▸

Solve the equation sec^2 x+ 2tan x = 0, 0 ≤ x ≤ 2π. IB May 2017 Exam


Write down the expansion of (cosx + isinx)^3. Hence, by using De Moivre's theorem, find cos3x in terms of powers of cosx.


Find the coordinates and determine the nature of the stationary points of curve y=(2/3)x^3+2x^2-6x+3


Two functions, y1 & y2, are given by y1=x^2+16x+4; y2=2(3x+2). Find analytically the volume of the solid created by revolving the area between the two curves by 2pi radians around the x-axis. N.B. y2>y1 on the interval between the points of intersection.