Describe the process of oxygen transport via haemoglobin.

Haemoglobin is a complex metal ion consisting of hexa-coordinated Fe2+ ions. With 6 coordinate bonds, haemoglobin forms an octahedral shape where 4 nitrogen ligands form a haem disc, a globin molecule forms the 5th bond, and the final bond can be interchanged between H2O and O2. An equilibrium is established by this 6th bond, following the equation: Hb(H2O)4 + 4O2 <=> Hb(O4) + 4H2O. In the lungs, oxygen concentration is higher, or increased, so equilibrium shifts right to oppose the change, meaning the H2O ligands are substituted for O2 ligands to form oxyhaemoglobin to carry oxygen through the blood. As the oxyhaemoglobin arrives at respiring tissues, oxygen concentration is low, while water concentration is higher due to respiration. Equilibrium shifts left to oppose the change, and oxygen is exchanged with water molecules. When haemoglobin reaches the lungs again, the process repeats.

Answered by Chemistry tutor

4243 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Explain the resistance to bromination of benzene in comparison to phenol.


Describe the Structure and Bonding of Benzene


What is an acid-base pair?


Why does the solubility of Group 2 hydroxides in water increase down the group?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences