What is a disproportionation reaction?

A disproportionation reaction is when an element is both oxidised and reduced in the same reaction. You check this by looking at the oxidation state of the element at the begining of the reaction and then what it is in the two products at the end; if the oxidation state has gone up (i.e it has lost electrons) it has been oxidised, and if the oxidation state has gone down (i.e it has gained electrons) it has been reduced. Remember OILRIG to help;

Oxidation Is Loss (of electrons) Reduction Is Gain (of electrons)

An example is the disproportionation of copper in the following reaction:

Cu2O (aq) +  H2SO4 (aq) --> Cu (s) + CuSO4 (aq) + H2O (l)

Here the copper goes from oxidation state +1 in Cu2O to oxidation state 0 in Cu and oxidation state +2 in CuSO4.

MV
Answered by Mia V. Chemistry tutor

57622 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

A student reacts 50.0cm^3 of 2.00mol dm^-3 HCl with 25.0cm^3 NaOH. What is the concentration of NaOH?


What is orbital hybridisation and its relevance?


In terms of the structure and boiling point of graphite, explain why the melting point is high


Which chemical would have a higher boiling point 1,3-dimethylbutane or hexane


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning