By taking the initial vertical speed as v_{v} = 6 sin(60) = 5.2 ms^{-1}.The max height of the ball is given by v_{v}^{2} = u_{v}^{2} + 2as. From this, s = 1.4m.Knowing the hieght, we can find the time that the ball spends in the air. To reach max height, use v = u + at to calculate t = 0.53. Then from max height, the ball falls a distance of 0.4m. To calculate how long it takes to fall this distance, use s = ut +0.5at^{2} .As we now know the total time it takes for the ball to reach the hoop, we can calculate the horizontal distance the ball traveled.The horizontal speed, calculated by v = cos(60) = 3 ms^{-1} can be used to measure the distance using simple time distance velocity formula, s = t/v = 2.46