Explain how nucleophilic substitution for a haloalkane actually occurs?

In a haloalkane, not all of the bonds are the same. We have to consider the fact that the halogen atom (for instance a bromine atom) is more electronegative than either carbon or hydrogen atoms, and has a tendency to withdraw electron density towards itself. This makes the C-Br bond polarised. The carbon atom has had electron density removed from itself, and now has a partial positive charge. Thus, it is more susceptible to attack by a species with a high electron density, or a negative charge. Such a species is called a nucleophile. A cyanide ion, for example, has a formal negative charge on the carbon.As like and unlike charges attract, the negative cyanide ion will attack the positive carbon atom, and in doing so will displace the bromide ion. This is nucleophilic substitution.

NK
Answered by Naman K. Chemistry tutor

2592 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Explain the trend in ionization energy down a group of the periodic table.


3-Methylpent-2-ene (CH3CH=C(CH3)CH2CH3) reacts with Hydrogen Chloride(HCl) forming a major and minor product. Please name the reaction, draw the mechanism for the formation of the major product and briefly explain why there is a major and a minor product.


The enthalpy of combustion of ethanol is −1371 kJ mol−1 . The density of ethanol is 0.789 g cm−3 . Calculate the heat energy released in kJ when 1 dm3 of ethanol is burned.


Potassium Chlorate(VII) decomposes to produce Potassium Chloride and Oxygen. Using the following data calculate the enthalpy change of this decomposition: Enthalpy of formation(KClO4) = -430 kJ mol-1, Enthalpy of formation(KCl) = -440 kJ mol-1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning