Find the general solution to the differential equation; y'' + 4y' = 24x^2

The first step in tackling any second order differential equation is to find the Auxiliary Function. Looking at the equation's left hand side, we can find the derivative terms - we will substitute the derivative terms with another variable m, which we can then solve to find a suitable Complementary Function (CF). For second order terms, or any y'' terms, we use m2, then use m for first order terms (y'). If zero order terms exist, then only the coefficient will remain. Hence, y'' + 4y' becomes m2 + 4m. We then attempt to solve this auxiliary function by solving for m2 + 4m = 0, for which we get m = 0, -4. In this case, since we have two unique terms (we can also get a repeated solution and complex conjugate solutions), we can say that the CF is equal to Ae(m1)x + Be(m2)x, where A and B are constants. In this problem, our complementary function is A + Be-4x.
Since this is a non-homogeneous equation, we must consider the non-derivative x term on the right hand side of the equation - we need to form a Particular Integral (PI) that will add to the CF to give the final solution. Since there is no x2 term in the CF, we can assign the form of the PI as px3 + qx2 + rx. This particular integral will now need to substituted back into the differential equation to find the value of the constants p, q and r. The first and second derivatives of the PI are 3px2 + 2qx + r and 6px + 2q respectively. Substituting this into the differential equation gives 6px + 2q + 4(3px2 + 2qx + r) = 24x2. By equating the coefficients of each term, we find that p = 2, q = -1.5, r = 0.75. This gives our final PI as 2x3 - 1.5x2 + 0.75x.
The final step in this question is to add together the CF and PI to give the general solution. Therefore, the general solution is: Y = A + Be-4x + 2x3 - 1.5x2 + 0.75x. The reason this is the general solution and not a particular solution is because it still has the constants A and B - you require at least two sets of limits to solve for those constants.

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