Are the integers a group under addition? How about multiplication?

There are 4 things we need for a group: associativity, the existence of an identity, inverses in the group and closure. The integers are definitely associative under this operation as addition is associative as a + (b+c) = (a +b) + c. the identity exits as 0 is an integer and for any integer A, A + 0 = A. The inverse exists in the integers as if A is in the integers, - A is too and A + (-A) = 0 = identity, and finally it is also closed as for two integers A and B, A + B is also an integer. Therefore it is a group.For multiplication it is not a group, as the identity for multiplication on the integers is 1, but say we choose an integer A, then the inverse is 1/A as A * 1/A = 1 = identity, but 1/A is in general not an integer, so the integers under multiplication do not form a group.

DC
Answered by Damon C. Further Mathematics tutor

5710 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

find all the roots to the equation: z^3 = 1 + i in polar form


Prove by induction that for all positive integers n , f(n) = 2^(3n+1) + 3*5^(2n+1) , is divisible by 17.


Find a vector that is normal to lines L1 and L2 and passes through their common point of intersection where L1 is the line r = (3,1,1) + u(1,-2,-1) and L2 is the line r = (0,-2,3) + v(-5,1,4) where u and v are scalar values.


A parabola with equation y^2=4ax for constant a is translated by the vector (2,3) to give the curve C. The curve C passes through the point (4,7), what is the value of a?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning