A satellite is in orbit of the Earth, and moves at a constant orbital speed of 3055.5m/s. If it is at an altitude of 35786km, calculate the time period for a complete cycle, giving your answer in hours. Answer should be given in in 3 significant figures.

Orbital Speed = [2Π(Orbital Radius)]/Time Period
3055.5m/s = 10999.8km/h
therefore:
10999.8km/h = [2Π(35786km)]/TT = [2Π(35786km)]/(10999.8km/h)T = 20.4 hours

Answered by Physics tutor

2367 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

(A-level but box won't let me change it from GCSE) A particle of charge q and initial speed v is stopped by a potential difference V in distance d and time t. What was its initial momentum?


What is Newton's first law of motion?


Describe the ways energy can be transmitted through a substance?


What's the difference between distance and displacement


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning