A satellite is in orbit of the Earth, and moves at a constant orbital speed of 3055.5m/s. If it is at an altitude of 35786km, calculate the time period for a complete cycle, giving your answer in hours. Answer should be given in in 3 significant figures.
Orbital Speed = [2Π(Orbital Radius)]/Time Period
3055.5m/s = 10999.8km/h
therefore:
10999.8km/h = [2Π(35786km)]/TT = [2Π(35786km)]/(10999.8km/h)T = 20.4 hours
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