The equation of a curve is y = x^2 - 5x. Work out dy/dx
This is an example of differentiation. This can be useful in many concepts, one being finding the gradient of a line or curve at a certain point. To differentiate these types of equations, the rule is to multiply the front by the power and to take one from the power!y = x^2 - 5xWe will take each part separately. Starting with x^2. We multiply the front (which is 1) by the power (which is 2), therefore the constant at the front is now 2. We take one from the power, so 2 - 1 = 1. Therefore the derivative of x^2 is 2x.Next we take 5x. Multiply the front (5) by the power (1), and take 1 from the power (1 - 1 = 0). Therefore the derivative of 5x is 5.Now, we put it all together! dy/dy = 2x - 5!
VL
Answered by Venetia L. • Further Mathematics tutor
9577 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸In a chess club there are x boys and y girls. If ten more boys join and one more girl joins, there is an equal amount of boys and girls. Knowing that y = 2x+2, Calculate x and y. [4 marks]
Point A lies on the curve: y=x^2+5*x+8. The x-coordinate of A is -4. What is the equation of the normal to the curve at A?
A curve has equation y = ax^2 + 3x, when x= -1, the gradient of the curve is -5. Work out the value of a.
Given a^2 < 4 and a+2b = 8. Work out the range of possible values of b. Give your answer as an inequality.