A 25 cm3 sample of an unknown concentration of sulfuric acid was titrated against 0.1 mol dm-3 sodium hydroxide. The average titre was 20 cm3. Calculate the concentration of the sulfuric acid.

Balanced equation: H2SO4 + 2NaOH → 2H2O + Na2SO4moles of NaOH = c x v = 0.1 mol dm-3 x (20/1000) dm3 = 0.002 molStoichiometry: H2SO4:NaOH = 1:2moles of H2SO4 = (0.002 mol)/2 = 0.001 molc=n/v= (0.001 mol)/((25/1000) dm3)= 0.04 mol dm-3

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Answered by Joseph K. Chemistry tutor

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