Given x^3 + 4x^2 + x - 6 = 0 , and one of the factors of this equation is (x-1), factorise and hence compute the other solutions for the eqaution.
Using either polynomial long division or by inspection, the equation can be reduced to:(x-1)(x2+5x+6)
The other bracket can the be factored out using inspection or the quadratic formula to give:(x-1)(x+2)(x+3)
Therefore, the remaining solutions to the equation are given as:x = -2 or x = -3
Related Maths Scottish Highers answers
All answers ▸Differentiate (with respect to x), y=2x^2+8x+5.
a) Factorise: 2x^2-72, and hence b) find the y-intercept of the line with the equation: y=(2x^2-72)/(4x-24)
Find ∫((x^2−2)(x^2+2)/x^2) dx, x≠0
Show that (𝑥 − 1) is a factor of 𝑓(𝑥)=2𝑥^3 + 𝑥^2 − 8𝑥+ 5. Hence fully factorise 𝑓(𝑥) fully.