Given x^3 + 4x^2 + x - 6 = 0 , and one of the factors of this equation is (x-1), factorise and hence compute the other solutions for the eqaution.

Using either polynomial long division or by inspection, the equation can be reduced to:(x-1)(x2+5x+6)
The other bracket can the be factored out using inspection or the quadratic formula to give:(x-1)(x+2)(x+3)
Therefore, the remaining solutions to the equation are given as:x = -2 or x = -3

Answered by Maths tutor

1160 Views

See similar Maths Scottish Highers tutors

Related Maths Scottish Highers answers

All answers ▸

Determine for what values of c, f(x)=4x^2-(2c+8)x+4 has no real roots.


Describe an exponential function and the exponential decay equation.


Solve algebraically the system of equations: 4x+5y=-3 and 6x-2y=5


Show that (𝑥 − 1) is a factor of 𝑓(𝑥)=2𝑥^3 + 𝑥^2 − 8𝑥+ 5. Hence fully factorise 𝑓(𝑥) fully.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences