Given x^3 + 4x^2 + x - 6 = 0 , and one of the factors of this equation is (x-1), factorise and hence compute the other solutions for the eqaution.

Using either polynomial long division or by inspection, the equation can be reduced to:(x-1)(x2+5x+6)
The other bracket can the be factored out using inspection or the quadratic formula to give:(x-1)(x+2)(x+3)
Therefore, the remaining solutions to the equation are given as:x = -2 or x = -3

Answered by Maths tutor

1400 Views

See similar Maths Scottish Highers tutors

Related Maths Scottish Highers answers

All answers ▸

Determine for what values of c, f(x)=4x^2-(2c+8)x+4 has no real roots.


a) Factorise: 2x^2-72, and hence b) find the y-intercept of the line with the equation: y=(2x^2-72)/(4x-24)


A circle has equation x^2+y^2-8x+10y+41=0. A point on the circle has coordinates (8,-3). Find the equation of the tangent to the circle passing through this point.


PQR is a triangle with vertices P (−2, 4), Q(4, 0) and R (3, 6). Find the equation of the median through R.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning