Solve (x-1)^2-2(x-1)-3=0

Solving this equation would mean finding the values of x that satisfy it equating to zero. Therefore, to start, you must simplify the equation by expanding all the values to get (x^2-2x+1)-(2x-2)-3=0 [expanding (x-1)^2 by multiplying (x-1)(x-1)] and further expanding and simplifying it to get x^2-4x=0. Once we have a simplified version of the equation, we can then factorise this in order to solve for x. In order to factorise this equation, we can take out a factor of x to get x(x-4)=0 whereby we can see that x multiplied by (x-4) equals to zero suggesting that one of the two values must be equal to zero because anything multiplied by zero is zero. Therefore, there must be two solutions to the equation. x must be equal to 0 or 4 because when x is 0, the equation is zero and when x is 4, the equation is also satisfied.Therefore the answer is x=0 or x=4.

EL

Related Maths 13 Plus answers

All answers ▸

why is (x+y)^2 ≠ x^2 + y^2


There is a right-angle triangle with hypothenus H = 5 cm and side A = 3 cm. Find the length of the third side B using Pythagoras' Theorem.


E = {Students in Year 12} G = {Students who study German} F = {Students who study French} M = {Students who study Maths} (i) G ∩ M = Ø Use this information to write a statement about the students who study German in Year 12


Mike has 4 blue balls, 6 green balls and 10 yellow balls what is the probability that he will pick a yellow ball.